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mysql> select a.id,a.name,b.dept_id -> from emp a left join emp_dept b on (a.id=b.emp_id) -> where b.dept_id IS NULL;
+----+-----------+---------+ | id | name | dept_id | +----+-----------+---------+ | 6 | Dennis-6 | NULL | | 7 | Dennis-7 | NULL | | 8 | Dennis-8 | NULL | | 9 | Dennis-9 | NULL | | 10 | Dennis-10 | NULL | +----+-----------+---------+
# 把 table emp_dept 放在左边的情形(当然以 emp_dept 中的数据为基础来显示资料,emp 中比emp_dept 中多的资料也就不会显示出来了):
select a.id,a.name,b.dept_idphpma.com from emp_dept b left join emp a on (a.id=b.emp_id); mysql> select a.id,a.name,b.dept_id -> from emp_dept b left join emp a on (a.id=b.emp_id); +------+----------+---------+ | id | name | dept_id | +------+----------+---------+ | 2 | Dennis-2 | DEv | | 1 | Dennis-1 | R&D | | 3 | Dennis-3 | R&D | | 4 | Dennis-4 | Test | | 5 | Dennis-5 | Test | +------+----------+---------+
>> right join ---------------phpma.com select a.id,a.name,b.dept_id from emp a right join emp_dept b on (a.id=b.emp_id); # 挑资料时以右边 table emp_dept 中的资料为基础来显示资料
mysql> select a.id,a.name,b.dept_id -> from emp a right join emp_dept b on (a.id=b.emp_id);
+------+----------+---------+ | id | name | dept_id | +------+----------+---------+ | 2 | Dennis-2 | DEv | | 1 | Dennis-1 | R&D | | 3 | Dennis-3 | R&D | | 4 | Dennis-4 | Test | | 5 | Dennis-5 | Test | +------+----------+---------+ 5 rows in set (0.00 sec)
# 我们再把 table 的位置交换一下,再用 right join 试试
select a.id,a.name,b.dept_id from emp_dept b right join emp a on (a.id=b.emp_id);
(阅读次数:)
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